What is Darrell Arthur's full name?
Darrell Arthur
Darrell Arthur date of birth:
March 25, 1988
How old is Darrell Arthur?
38
Where was Darrell Arthur born?
Dallas, Texas
How tall is Darrell Arthur?
6' 9" (206 cm)
How much does Darrell Arthur weigh?
225 lbs (102.1 kg)
What is Darrell Arthur nationality?
American
Where did Darrell Arthur go to school?
South Oak Cliff in Dallas, Texas
Where did Darrell Arthur go to university?
University of Kansas
What is Darrell Arthur's occupation?
Basketball player
Short Biography
Darrell Antwonne Arthur (born March 25, 1988) is an American professional basketball player for the Denver Nuggets of the National Basketball Association (NBA). He played college basketball for the Kansas Jayhawks for two seasons where he was part of the 2007–08 national championship team. He was originally drafted by the New Orleans Hornets in the 2008 NBA draft but after two trades, he ended up with the Memphis Grizzlies, with whom he signed on July 8, 2008. He is listed at 6'9", 235 lb (107 kg) and plays the power forward position.