What is Art Schult's middle name?
William
What is Art Schult's full name?
Arthur William Schult
Art Schult nickname(s):
Dutch
Art Schult date of birth:
June 20, 1928
How old was Art Schult when died?
86
Where was Art Schult born?
Brooklyn, NY
When did Art Schult die?
July 25, 2014
How tall is Art Schult?
6' 3" (190 cm)
How much does Art Schult weigh?
210 lbs (95.3 kg)
What is Art Schult nationality?
American
Where did Art Schult go to university?
Georgetown University
What is Art Schult's occupation?
Former Major League Baseball Player
Short Biography
Arthur William "Dutch" Schult (June 20, 1928 – July 25, 2014) was an American professional baseball player. Schult was an outfielder and first baseman who played in 164 games over five seasons for the New York Yankees, Cincinnati Redlegs, Washington Senators and the Chicago Cubs. He stood 6 feet 3 inches (1.91 m) tall, weighed 210 pounds (95 kg), and batted and threw right-handed.