Abraham Weinberg nickname(s):
Abraham "Bo" Weinberg, Bo Weinberg
Abraham Weinberg date of birth:
January 7, 1897
How old was Abraham Weinberg when died?
38
Where was Abraham Weinberg born?
Manhattan, New York City, New York, United States
When did Abraham Weinberg die?
September 9, 1935
Where did Abraham Weinberg die?
Manhattan, New York City, New York, United States
Abraham Weinberg body shape:
Average
What color is Abraham Weinberg's hair?
Black
Is Abraham Weinberg gay or straight?
Straight
What religion is Abraham Weinberg?
Jewish
What is Abraham Weinberg's ethnicity?
White
What is Abraham Weinberg nationality?
American
What is Abraham Weinberg's occupation?
Hitman, bootlegger
Short Biography
Abraham "Bo" Weinberg (January 7, 1900 – September 9, 1935) was a Jewish New York City mobster who became a hitman and chief lieutenant for the Prohibition-era gang boss Dutch Schultz. As Schultz expanded his bootlegging operations into Manhattan during Prohibition, he recruited Abe Weinberg and his brother George into his gang. Abe Weinberg would become one of Schultz's top gunmen during the Manhattan Bootleg Wars and was a later suspect in the high-profile gangland slayings of Jack "Legs" Diamond, Vincent "Mad Dog" Coll, and mob boss Salvatore Maranzano.