Abraham Weinberg nickname(s):

Abraham "Bo" Weinberg, Bo Weinberg

Abraham Weinberg date of birth:

January 7, 1897

How old was Abraham Weinberg when died?

38

Where was Abraham Weinberg born?

Manhattan, New York City, New York, United States

When did Abraham Weinberg die?

September 9, 1935

Where did Abraham Weinberg die?

Manhattan, New York City, New York, United States

Abraham Weinberg body shape:

Average

What color is Abraham Weinberg's hair?

Black

Is Abraham Weinberg gay or straight?

Straight

What religion is Abraham Weinberg?

Jewish

What is Abraham Weinberg's ethnicity?

White

What is Abraham Weinberg nationality?

American

What is Abraham Weinberg's occupation?

Hitman, bootlegger

Short Biography

Abraham "Bo" Weinberg (January 7, 1900 – September 9, 1935) was a Jewish New York City mobster who became a hitman and chief lieutenant for the Prohibition-era gang boss Dutch Schultz. As Schultz expanded his bootlegging operations into Manhattan during Prohibition, he recruited Abe Weinberg and his brother George into his gang. Abe Weinberg would become one of Schultz's top gunmen during the Manhattan Bootleg Wars and was a later suspect in the high-profile gangland slayings of Jack "Legs" Diamond, Vincent "Mad Dog" Coll, and mob boss Salvatore Maranzano.